Previous posts in this serie:
- Which indexes are not used in my database? Index usage statistics and disk space usage.
- Defragmentation clustered indexes.
- Online nonclustered index defragmentation.
With next script you can retrieve all double indexes in your database.
CREATE VIEW vw_index_list AS
SELECT tbl.[name] AS TableName,
idx.[name] AS IndexName,
INDEX_COL( tbl.[name], idx.indid, 1 ) AS col1,
INDEX_COL( tbl.[name], idx.indid, 2 ) AS col2,
INDEX_COL( tbl.[name], idx.indid, 3 ) AS col3,
INDEX_COL( tbl.[name], idx.indid, 4 ) AS col4,
INDEX_COL( tbl.[name], idx.indid, 5 ) AS col5,
INDEX_COL( tbl.[name], idx.indid, 6 ) AS col6,
INDEX_COL( tbl.[name], idx.indid, 7 ) AS col7,
INDEX_COL( tbl.[name], idx.indid, 8 ) AS col8,
INDEX_COL( tbl.[name], idx.indid, 9 ) AS col9,
INDEX_COL( tbl.[name], idx.indid, 10 ) AS col10,
INDEX_COL( tbl.[name], idx.indid, 11 ) AS col11,
INDEX_COL( tbl.[name], idx.indid, 12 ) AS col12,
INDEX_COL( tbl.[name], idx.indid, 13 ) AS col13,
INDEX_COL( tbl.[name], idx.indid, 14 ) AS col14,
INDEX_COL( tbl.[name], idx.indid, 15 ) AS col15,
INDEX_COL( tbl.[name], idx.indid, 16 ) AS col16,
dpages,
used,
rowcnt
FROM SYSINDEXES idx
INNER JOIN SYSOBJECTS tbl ON idx.[id] = tbl.[id]
WHERE indid > 0
AND INDEXPROPERTY( tbl.[id], idx.[name], 'IsStatistics') = 0
GO
SELECT l1.tablename,
l1.indexname,
l2.indexname AS duplicateIndex,
l1.col1, l1.col2, l1.col3, l1.col4, l1.col5, l1.col6, l1.col7, l1.col8,
l1.col9, l1.col10, l1.col11, l1.col12, l1.col13, l1.col14, l1.col15, l1.col16,
l1.dpages,l1.used,l1.rowcnt
FROM vw_index_list l1
INNER JOIN vw_index_list l2 ON l1.tablename = l2.tablename
AND l1.indexname <> l2.indexname
AND l1.col1 = l2.col1
AND COALESCE(l1.col2,'') = COALESCE(l2.col2,'')
AND COALESCE(l1.col3,'') = COALESCE(l2.col3,'')
AND COALESCE(l1.col4,'') = COALESCE(l2.col4,'')
AND COALESCE(l1.col5,'') = COALESCE(l2.col5,'')
AND COALESCE(l1.col6,'') = COALESCE(l2.col6,'')
AND COALESCE(l1.col7,'') = COALESCE(l2.col7,'')
AND COALESCE(l1.col8,'') = COALESCE(l2.col8,'')
AND COALESCE(l1.col9,'') = COALESCE(l2.col9,'')
AND COALESCE(l1.col10,'') = COALESCE(l2.col10,'')
AND COALESCE(l1.col11,'') = COALESCE(l2.col11,'')
AND COALESCE(l1.col12,'') = COALESCE(l2.col12,'')
AND COALESCE(l1.col13,'') = COALESCE(l2.col13,'')
AND COALESCE(l1.col14,'') = COALESCE(l2.col14,'')
AND COALESCE(l1.col15,'') = COALESCE(l2.col15,'')
AND COALESCE(l1.col16,'') = COALESCE(l2.col16,'')
ORDER BY
l1.tablename,
l1.indexname
GO
DROP VIEW Vw_index_list
2 comments:
Also interesting is not 100% duplicate indexes but indexes that largely share the same frst set of columns. A query to retrieve those can be found on i.e. http://sqlblog.com/blogs/paul_nielsen/archive/2008/06/25/find-duplicate-indexes.aspx
I really like when people are expressing their opinion and thought. So I like the way you are writing
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